નીચેનાનું મૂલ્ય શોધો: $\begin{bmatrix} -1 & 4 & -6 \\ 8 & 5 & 16 \\ 2 & 8 & 5 \end{bmatrix} + \begin{bmatrix} 12 & 7 & 6 \\ 8 & 0 & 5 \\ 3 & 2 & 4 \end{bmatrix}$

  • A
    $\begin{bmatrix} 11 & 11 & 0 \\ 16 & 5 & 21 \\ 5 & 10 & 9 \end{bmatrix}$
  • B
    $\begin{bmatrix} 11 & 11 & 1 \\ 16 & 5 & 21 \\ 5 & 10 & 9 \end{bmatrix}$
  • C
    $\begin{bmatrix} 11 & 11 & 0 \\ 16 & 5 & 20 \\ 5 & 10 & 9 \end{bmatrix}$
  • D
    $\begin{bmatrix} 11 & 11 & 0 \\ 16 & 5 & 21 \\ 5 & 10 & 8 \end{bmatrix}$

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Similar Questions

જો $A = [2]$ અને $B = \begin{bmatrix} 3 \\ 4 \end{bmatrix}$ હોય,તો $(BA)' = $ . . . . . . .

જો $A=\begin{bmatrix} b & a & 0 \\ c & 0 & b \\ a & a & b \end{bmatrix}$ અને $B=\begin{bmatrix} 0 & a & b \\ b & 0 & c \\ b & a & a \end{bmatrix}$ બે શ્રેણિકો એવા છે કે જેથી $AB=\begin{bmatrix} 2 & 2 & 7 \\ 1 & 8 & 5 \\ 3 & 6 & 10 \end{bmatrix}$, તો $a^2+b^2+c^2=$

જો $A, B, C$ એ ત્રણ $n \times n$ શ્રેણિકો હોય,તો $(ABC)' = $

આપેલ ગુણાકારની ગણતરી કરો: $\begin{bmatrix} a & b \\ -b & a \end{bmatrix} \begin{bmatrix} a & -b \\ b & a \end{bmatrix}$

જો $A = \begin{bmatrix} 1 & -2 & 1 \\ 2 & 1 & 3 \end{bmatrix}$ અને $B = \begin{bmatrix} 2 & 1 \\ 3 & 2 \\ 1 & 1 \end{bmatrix}$ હોય,તો $(AB)^T$ બરાબર શું થાય?

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